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微信小程序消息推送解密

2025/7/8 4:39:46 来源:https://blog.csdn.net/weixin_42209307/article/details/145756313  浏览:    关键词:微信小程序消息推送解密
package com.test.main.b2b;import org.apache.commons.codec.binary.Base64;import javax.crypto.Cipher;
import javax.crypto.spec.IvParameterSpec;
import javax.crypto.spec.SecretKeySpec;
import java.util.Arrays;/*** @author * @version 1.0* @description: 解谜微信小程序消息通知* @date 2025/2/20 15:29*/
public class 支付回调解密 {// EncodingAESKey(消息加密密钥)public static String encodingAesKey = "sdIeXprnCzbVmDIp";// Encrypt Msgpublic static String encryptedData = "urMQfiTkA+nLIV/gpAxwQaFurMQfiTkA+nLIV/gpAxwQaFurMQfiTkA+nLIV/gpAxwQaFurMQfiTkA+nLIV/gpAxwQaFurMQfiTkA+nLIV/gpAxwQaFurMQfiTkA+nLIV/gpAxwQaF";public static void main(String[] args) throws Exception {// 请替换成你的真实数据String decrypt = decrypt(encryptedData, encodingAesKey);System.out.println(decrypt);}public static String decrypt(String encryptedMsg, String encodingAesKey) throws Exception {// Base64解码密钥(微信EncodingAESKey是Base64编码的)byte[] aesKey = Base64.decodeBase64(encodingAesKey + "=");byte[] original;try {// 设置解密模式为AES的CBC模式Cipher cipher = Cipher.getInstance("AES/CBC/NoPadding");SecretKeySpec key_spec = new SecretKeySpec(aesKey, "AES");IvParameterSpec iv = new IvParameterSpec(Arrays.copyOfRange(aesKey, 0, 16));cipher.init(Cipher.DECRYPT_MODE, key_spec, iv);// 使用BASE64对密文进行解码byte[] encrypted = Base64.decodeBase64(encryptedMsg);// 解密original = cipher.doFinal(encrypted);} catch (Exception e) {e.printStackTrace();throw new AesException(AesException.DecryptAESError);}String xmlContent;try {// 去除补位字符byte[] bytes = PKCS7Encoder.decode(original);// 分离16位随机字符串,网络字节序和AppIdbyte[] networkOrder = Arrays.copyOfRange(bytes, 16, 20);int xmlLength = recoverNetworkBytesOrder(networkOrder);xmlContent = new String(Arrays.copyOfRange(bytes, 20, 20 + xmlLength), "UTF-8");} catch (Exception e) {e.printStackTrace();throw new AesException(AesException.IllegalBuffer);}return xmlContent;}// 还原4个字节的网络字节序static int recoverNetworkBytesOrder(byte[] orderBytes) {int sourceNumber = 0;for (int i = 0; i < 4; i++) {sourceNumber <<= 8;sourceNumber |= orderBytes[i] & 0xff;}return sourceNumber;}
}

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