lua判断子串，字符串替换，字符串分割

故事背景，需要在聊天做一个gm命名，如果输入的字符串带有'@'，则根据后面的参数调用函数。匹配函数的时候需要去掉"@"。字符串还需要切割成函数名和参数。
 

function string.split(input, delimiter)input = tostring(input)delimiter = tostring(delimiter)if (delimiter=='') then return false endlocal pos,arr = 0, {}-- for each divider foundfor st,sp in function() return string.find(input, delimiter, pos, true) end dotable.insert(arr, string.sub(input, pos, st - 1))pos = sp + 1endtable.insert(arr, string.sub(input, pos))return arr
endlocal content = "@additem 1 1"
if content:find("@") thenprint("gm")
end
local content = string.gsub(content, "@", '')
print(content)local t = string.split(content," ")
for k,v in pairs(t)doprint(v)
end